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Composite Thermal Barrier
Introduction
This example shows how to set up multiple sandwiched thin layers with different thermal conductivities in two different ways.
First, the composite is modeled as a 3D object. In the second approach, the Thin Layer boundary condition is used to avoid resolving the thin domains, and two modeling options of this feature are compared.
The methodology is useful when modeling heat transfer through thermal barriers like multilayer coatings.
See Lumped Composite Thermal Barrier for a comparison of the 3D approach with a 0D approach using the Thermal Connection feature and the Lumped Thermal System interface.
Model Definition
This tutorial uses a simple geometry as shown in Figure 1. The cylinder has a radius of 2 cm and a height of 4 cm.
Figure 1: Geometry.
The composite consists of two layers with different thermal conductivities. The first approach resolves each layer as a 3D domain. The height of the layers is about three orders of magnitude smaller than the bulk height. This often requires to build a mesh manually to accurately resolve the thin structure.
COMSOL Multiphysics provides a special boundary condition which is available from the Heat Transfer Module, namely the Thin Layer feature.
The second approach first uses this feature with resistive property (Thermally thick approximation option). This simplifies the geometry and thus the mesh by representing the thermal barrier as a boundary. In complex geometries, this boundary condition can reduce the amount of memory and time required for the simulation significantly.
The underlying equation assumes the heat flux through the layer proportional to the temperature difference between upper and lower bulk. It is based on the assumption that the bulk on each side is well stirred so that all resistance against heat transfer is within a thin layer near the wall. Due to the additivity of resistance the flux over the composite can be lumped to
where the overall thermal conductivity ktot can be calculated as
Then, the second approach uses the General option of the Thin Layer feature. In this case, an extra-dimension is defined on the boundary to resolve the heat flux both in tangential and normal direction in the layers.
Material Properties
The cylinder is made of steel. The composite consists of two layers of different ceramics.
Table 1: Ceramics Material Properties.
Property
Ceramic 1
Ceramic 2
Thermal conductivity
1 W/(m·K)
0.5 W/(m·K)
Density
6000 kg/m3
5800 kg/m3
Heat capacity at constant pressure
320 J/(kg·K)
280 J/(kg·K)
Boundary Conditions
The temperature at the bottom is fixed to 20°C whereas one half of the top boundary is held at 1220°C (1493 K). All other outer boundaries are perfectly insulated.
Results and Discussion
Figure 2 shows the temperature distribution in the cylinder. The composite acts as a thermal barrier resulting in a jump of the temperature over the layer.
Figure 2: Temperature distribution.
Of interest is if the thin layer boundary condition produces reliable results compared to resolving the thin layers in 3D. This can be done with a comparative line graph as in Figure 3. It shows that the 2D approach, with or without a 1D extra dimension, produces accurate results for the bulk temperatures.
Figure 3: Temperature profile for 3D, 2D, and 2D with extra dimension approaches.
Another important question for simulating is the influence on the mesh size and on the required RAM.
With the default tetrahedral mesh the number of mesh elements is about 130,000 elements and the meshing algorithm gives some warnings.
With the swept mesh feature you can significantly reduce the number of elements to about 2800 elements which is only 2% of the initial number of elements. In complex geometries the swept mesh algorithm is often not applicable. Using the thin layer boundary condition, the number of mesh elements reduces from 2800 to 2000 which is about 30% less, even in this simple geometry. You can see the number of mesh elements used in the Messages window below the Graphics window.
Notes About the COMSOL Implementation
To compare the results directly, both approaches are handled in a single MPH-file.
Application Library path: Heat_Transfer_Module/Tutorials,_Thin_Structure/composite_thermal_barrier
Modeling Instructions
From the File menu, choose New.
New
In the New window, click  Model Wizard.
Model Wizard
1
In the Model Wizard window, click  3D.
2
In the Select Physics tree, select Heat Transfer > Heat Transfer in Solids (ht).
3
Click Add.
4
Click  Study.
5
In the Select Study tree, select General Studies > Stationary.
6
Click  Done.
Global Definitions
Parameters 1
1
In the Model Builder window, under Global Definitions click Parameters 1.
2
In the Settings window for Parameters, locate the Parameters section.
3
In the table, enter the following settings:
Name
Expression
Value
Description
d_ceram1
50[um]
5E-5 m
Thickness of layer 1
d_ceram2
75[um]
7.5E-5 m
Thickness of layer 2
T_hot
1220[degC]
1493.2 K
Hot temperature
Geometry 1
1
In the Model Builder window, under Component 1 (comp1) click Geometry 1.
2
In the Settings window for Geometry, locate the Units section.
3
From the Length unit list, choose cm.
Cylinder 1 (cyl1)
1
In the Geometry toolbar, click  Cylinder.
2
In the Settings window for Cylinder, locate the Size and Shape section.
3
In the Radius text field, type 2.
4
In the Height text field, type 4.
5
In the Geometry toolbar, click  Build All.
Now, create thin cylinders to define the ceramic layers between the two steel domains.
Cylinder 2 (cyl2)
1
In the Geometry toolbar, click  Cylinder.
2
In the Settings window for Cylinder, locate the Size and Shape section.
3
In the Radius text field, type 2.
4
In the Height text field, type d_ceram1.
5
Locate the Position section. In the z text field, type 2-(d_ceram1+d_ceram2)/2.
6
In the Geometry toolbar, click  Build All.
Cylinder 3 (cyl3)
1
In the Geometry toolbar, click  Cylinder.
2
In the Settings window for Cylinder, locate the Size and Shape section.
3
In the Radius text field, type 2.
4
In the Height text field, type d_ceram2.
5
Locate the Position section. In the z text field, type 2-(d_ceram1+d_ceram2)/2+d_ceram1.
6
In the Geometry toolbar, click  Build All.
Line Segment 1 (ls1)
1
In the Geometry toolbar, click  More Primitives and choose Line Segment.
2
In the Settings window for Line Segment, locate the Starting Point section.
3
From the Specify list, choose Coordinates.
4
In the y text field, type -2.
5
In the z text field, type 4.
6
Locate the Endpoint section. From the Specify list, choose Coordinates.
7
In the y text field, type 2.
8
In the z text field, type 4.
9
Click  Build All Objects.
Definitions
Create operators and variables to evaluate the average temperature in the thermal barrier and in each of its layers.
Integration : Barrier
1
In the Model Builder window, expand the Component 1 (comp1) > Definitions node.
2
Right-click Definitions and choose Nonlocal Couplings > Integration.
3
In the Settings window for Integration, locate the Source Selection section.
4
Click  Paste Selection.
5
In the Paste Selection dialog, type 2 3 in the Selection text field.
6
Click OK.
7
In the Settings window for Integration, type intopBarrier in the Operator name text field.
8
In the Label text field, type Integration : Barrier.
Integration : Layer 1
1
Right-click Integration : Barrier and choose Duplicate.
2
In the Settings window for Integration, locate the Source Selection section.
3
In the list, select 3.
4
Click  Remove from Selection.
5
Select Domain 2 only.
6
In the Label text field, type Integration : Layer 1.
7
In the Operator name text field, type intopLayer1.
Integration : Layer 2
1
In the Model Builder window, under Component 1 (comp1) > Definitions right-click Integration : Barrier (intopBarrier) and choose Duplicate.
2
In the Settings window for Integration, locate the Source Selection section.
3
In the list, select 2.
4
Click  Remove from Selection.
5
Select Domain 3 only.
6
In the Label text field, type Integration : Layer 2.
7
In the Operator name text field, type intopLayer2.
Variables: temperature in thermal barrier
1
In the Model Builder window, right-click Definitions and choose Variables.
2
In the Settings window for Variables, locate the Variables section.
3
In the table, enter the following settings:
Name
Expression
Unit
Description
vol_barrier
intopBarrier(1)
m³
Volume of barrier
vol_layer1
intopLayer1(1)
m³
Volume of layer 1
vol_layer2
intopLayer2(1)
m³
Volume of layer 2
T_int_barrier
intopBarrier(T)
m³·K
Integral of temperature in thermal barrier
T_int_layer1
intopLayer1(T)
m³·K
Integral of temperature in layer 1
T_int_layer2
intopLayer2(T)
m³·K
Integral of temperature in layer 2
T_ave_barrier
intopBarrier(T)/intopBarrier(1)
K
Average of temperature in thermal barrier
T_ave_layer1
intopLayer1(T)/intopLayer1(1)
K
Average of temperature in layer 1
T_ave_layer2
intopLayer2(T)/intopLayer2(1)
K
Average of temperature in layer 2
4
In the Label text field, type Variables: temperature in thermal barrier.
Materials
Material Link 1 (matlnk1)
1
In the Model Builder window, under Component 1 (comp1) right-click Materials and choose More Materials > Material Link.
2
In the Settings window for Material Link, locate the Link Settings section.
3
Click  Add Material from Library.
Add Material to Material Link 1 (matlnk1)
1
Go to the Add Material to Material Link 1 (matlnk1) window.
2
In the tree, select Built-in > Steel AISI 4340.
3
Right-click and choose Add to Material Link 1 (matlnk1).
Materials
Material Link 2 (matlnk2)
1
Right-click Materials and choose More Materials > Material Link.
2
In the Settings window for Material Link, locate the Geometric Entity Selection section.
3
Click  Paste Selection.
4
In the Paste Selection dialog, type 2 in the Selection text field.
5
Click OK.
6
In the Settings window for Material Link, locate the Link Settings section.
7
Click  Blank Material.
8
In the Model Builder window, click Material Link 2 (matlnk2).
9
Click  Go to Material.
Global Definitions
Ceramic 1
1
In the Model Builder window, under Global Definitions > Materials click Material 2 (mat2).
2
In the Settings window for Material, type Ceramic 1 in the Label text field.
3
Locate the Material Contents section. In the table, enter the following settings:
Property
Variable
Value
Unit
Property group
Thermal conductivity
k_iso ; kii = k_iso, kij = 0
1[W/(m*K)]
W/(m·K)
Basic
Density
rho
6000[kg/m^3]
kg/m³
Basic
Heat capacity at constant pressure
Cp
320[J/(kg*K)]
J/(kg·K)
Basic
Materials
Material Link 3 (matlnk3)
1
In the Model Builder window, under Component 1 (comp1) right-click Materials and choose More Materials > Material Link.
2
In the Settings window for Material Link, locate the Geometric Entity Selection section.
3
Click  Paste Selection.
4
In the Paste Selection dialog, type 3 in the Selection text field.
5
Click OK.
6
In the Settings window for Material Link, locate the Link Settings section.
7
Click  Blank Material.
8
In the Model Builder window, click Material Link 3 (matlnk3).
9
Click  Go to Material.
Global Definitions
Ceramic 2
1
In the Model Builder window, under Global Definitions > Materials click Material 3 (mat3).
2
In the Settings window for Material, type Ceramic 2 in the Label text field.
3
Locate the Material Contents section. In the table, enter the following settings:
Property
Variable
Value
Unit
Property group
Thermal conductivity
k_iso ; kii = k_iso, kij = 0
0.5[W/(m*K)]
W/(m·K)
Basic
Density
rho
5800[kg/m^3]
kg/m³
Basic
Heat capacity at constant pressure
Cp
280[J/(kg*K)]
J/(kg·K)
Basic
Heat Transfer in Solids (ht)
Temperature 1
1
In the Physics toolbar, click  Boundaries and choose Temperature.
2
Select Boundary 3 only.
Temperature 2
1
In the Physics toolbar, click  Boundaries and choose Temperature.
2
Select Boundary 13 only.
3
In the Settings window for Temperature, locate the Temperature section.
4
In the T0 text field, type T_hot.
Mesh 1
First, mesh the top surface with a free triangular mesh and extrude it in layers through the cylindrical geometry. With a Distribution node, specify how many mesh layers are to be created within the domain. Resolve the composite layers with two elements in thickness.
Free Triangular 1
1
In the Mesh toolbar, click  More Generators and choose Free Triangular.
2
Select Boundaries 13 and 18 only.
3
In the Settings window for Free Triangular, click  Build Selected.
Swept 1
In the Mesh toolbar, click  Swept.
Distribution 1
1
Right-click Swept 1 and choose Distribution.
2
Select Domains 2 and 3 only.
3
In the Settings window for Distribution, locate the Distribution section.
4
In the Number of elements text field, type 2.
5
Click  Build All.
Study 1
In the Study toolbar, click  Compute.
Results
Change the unit of the temperature results to degrees Celsius.
Preferred Units 1
1
In the Results toolbar, click  Configurations and choose Preferred Units.
2
In the Settings window for Preferred Units, locate the Units section.
3
Click  Add Physical Quantity.
4
In the Physical Quantity dialog, select General > Temperature (K) in the tree.
5
Click OK.
6
In the Settings window for Preferred Units, locate the Units section.
7
In the table, enter the following settings:
Quantity
Unit
Preferred unit
Temperature
K
°C
8
Click  Apply.
Temperature, 3D Approach
The following plot is produced by default: temperature profile in the volume as in Figure 2.
1
In the Model Builder window, under Results click Temperature (ht).
2
In the Settings window for 3D Plot Group, type Temperature, 3D Approach in the Label text field.
Volume 1
1
In the Model Builder window, expand the Temperature, 3D Approach node, then click Volume 1.
2
In the Temperature, 3D Approach toolbar, click  Plot.
Next, create a temperature profile along the height of the cylinder. You will later compare the graph with the results of the 2D approach.
Temperature Profile
1
In the Results toolbar, click  1D Plot Group.
2
In the Settings window for 1D Plot Group, type Temperature Profile in the Label text field.
3
Locate the Plot Settings section.
4
Select the x-axis label checkbox. In the associated text field, type Height (cm).
5
Click to expand the Title section. From the Title type list, choose Manual.
6
In the Title text area, type Temperature Profile.
7
Locate the Legend section. From the Position list, choose Upper left.
Line Graph 1
1
In the Temperature Profile toolbar, click  Line Graph.
2
Select Edges 15, 17, 19, and 21 only.
3
In the Settings window for Line Graph, locate the x-Axis Data section.
4
From the Parameter list, choose Expression.
5
In the Expression text field, type z.
6
Click to expand the Coloring and Style section. From the Width list, choose 2.
7
Click to expand the Legends section. Select the Show legends checkbox.
8
From the Legends list, choose Manual.
9
In the table, enter the following settings:
Legends
Temperature, 3D approach
10
In the Temperature Profile toolbar, click  Plot.
Now let all the plots being regenerated after solving.
11
In the Model Builder window, click Results.
12
In the Settings window for Results, locate the Update of Results section.
13
Select the Recompute all plot data after solving checkbox.
Create now the second model which uses the Thin Layer feature and compare the results to the first approach.
Add Component
In the Model Builder window, right-click the root node and choose Add Component > 3D.
Add Physics
1
In the Home toolbar, click  Add Physics to open the Add Physics window.
2
Go to the Add Physics window.
3
In the tree, select Heat Transfer > Heat Transfer in Solids (ht).
4
Find the Physics interfaces in study subsection. In the table, clear the Solve checkbox for Study 1.
5
Click the Add to Component 2 button in the window toolbar.
6
In the Home toolbar, click  Add Physics to close the Add Physics window.
Add Study
1
In the Home toolbar, click  Add Study to open the Add Study window.
2
Go to the Add Study window.
3
Find the Studies subsection. In the Select Study tree, select General Studies > Stationary.
4
Find the Physics interfaces in study subsection. In the table, clear the Solve checkbox for Heat Transfer in Solids (ht).
5
Click the Add Study button in the window toolbar.
6
In the Home toolbar, click  Add Study to close the Add Study window.
Geometry 2
1
In the Settings window for Geometry, locate the Units section.
2
From the Length unit list, choose cm.
Cylinder 1 (cyl1)
1
In the Geometry toolbar, click  Cylinder.
2
In the Settings window for Cylinder, locate the Size and Shape section.
3
In the Radius text field, type 2.
4
In the Height text field, type 4.
5
Click to expand the Layers section. In the table, enter the following settings:
Layer name
Thickness (cm)
Layer 1
2
6
Clear the Layers on side checkbox.
7
Select the Layers on bottom checkbox.
8
In the Geometry toolbar, click  Build All.
Line Segment 1 (ls1)
1
In the Geometry toolbar, click  More Primitives and choose Line Segment.
2
In the Settings window for Line Segment, locate the Starting Point section.
3
From the Specify list, choose Coordinates.
4
In the y text field, type -2.
5
In the z text field, type 4.
6
Locate the Endpoint section. From the Specify list, choose Coordinates.
7
In the y text field, type 2.
8
In the z text field, type 4.
9
In the Geometry toolbar, click  Build All.
Definitions (comp2)
In order to make the comparison with Component 1, create an Integration operator and variables to evaluate the average temperature in the thermal barrier and in each of its layers.
Integration : Boundary
1
In the Model Builder window, expand the Component 2 (comp2) > Definitions node.
2
Right-click Component 2 (comp2) > Definitions and choose Nonlocal Couplings > Integration.
3
In the Settings window for Integration, type Integration : Boundary in the Label text field.
4
In the Operator name text field, type intopBnd.
5
Locate the Source Selection section. From the Geometric entity level list, choose Boundary.
6
Click  Paste Selection.
7
In the Paste Selection dialog, type 6 in the Selection text field.
8
Click OK.
Variables: temperature in thermal barrier
1
Right-click Definitions and choose Variables.
2
In the Settings window for Variables, locate the Variables section.
3
In the table, enter the following settings:
Name
Expression
Unit
Description
isLayer1
llmat1_xdim.atonly(dom==1)
 
Layer 1 identifier (=1 in layer 1, 0 elsewhere)
isLayer2
llmat1_xdim.atonly(dom==2)
 
Layer 2 identifier (=1 in layer 2, 0 elsewhere)
vol_barrier
intopBnd(ht2.sls2.xdintopall(1))
 
Volume of thermal barrier
vol_layer1
intopBnd(ht2.sls2.xdintopall(isLayer1))
 
Volume of layer 1
vol_layer2
intopBnd(ht2.sls2.xdintopall(isLayer2))
 
Volume of layer 2
T_int_barrier
intopBnd(ht2.sls2.xdintopall(T2))
 
Integral of temperature in thermal barrier
T_int_layer1
intopBnd(ht2.sls2.xdintopall(T2*isLayer1))
 
Integral of temperature in layer 1
T_int_layer2
intopBnd(ht2.sls2.xdintopall(T2*isLayer2))
 
Integral of temperature in layer 2
T_ave_barrier
T_int_barrier/vol_barrier
 
Average of temperature in thermal barrier
T_ave_layer1
T_int_layer1/vol_layer1
 
Average of temperature in layer 1
T_ave_layer2
T_int_layer2/vol_layer2
 
Average of temperature in layer 2
4
In the Label text field, type Variables: temperature in thermal barrier.
Materials
Material Link 4 (matlnk4)
In the Model Builder window, under Component 2 (comp2) right-click Materials and choose More Materials > Material Link.
Global Definitions
Layered Material 1 (lmat1)
1
In the Model Builder window, under Global Definitions right-click Materials and choose Layered Material.
2
In the Settings window for Layered Material, locate the Layer Definition section.
3
In the table, enter the following settings:
Layer
Material
Rotation (deg)
Thickness
Mesh elements
Layer 1
Ceramic 1 (mat2)
0.0
d_ceram1
2
4
Click  Add.
5
In the table, enter the following settings:
Layer
Material
Rotation (deg)
Thickness
Mesh elements
Layer 2
Ceramic 2 (mat3)
0.0
d_ceram2
2
Materials
Layered Material Link 1 (llmat1)
1
In the Model Builder window, under Component 2 (comp2) right-click Materials and choose Layers > Layered Material Link.
2
Select Boundary 6 only.
Heat Transfer in Solids 2 (ht2)
Add two Thin Layer nodes on the same boundary. They will be activated each in two separated studies, to compare the Thermally thick approximation and General options.
Thin Layer 1
1
In the Physics toolbar, click  Boundaries and choose Thin Layer.
2
Select Boundary 6 only.
Thin Layer 2
1
In the Physics toolbar, click  Boundaries and choose Thin Layer.
2
Select Boundary 6 only.
3
In the Settings window for Thin Layer, locate the Layer Model section.
4
From the Layer type list, choose General.
Temperature 1
1
In the Physics toolbar, click  Boundaries and choose Temperature.
2
Select Boundary 3 only.
Temperature 2
1
In the Physics toolbar, click  Boundaries and choose Temperature.
2
Select Boundary 7 only.
3
In the Settings window for Temperature, locate the Temperature section.
4
In the T0 text field, type T_hot.
Study 2
Step 1: Stationary
1
In the Model Builder window, under Study 2 click Step 1: Stationary.
2
In the Settings window for Stationary, locate the Physics and Variables Selection section.
3
Select the Modify model configuration for study step checkbox.
Disable Thin Layer 2 in this study. First, Thin Layer 1 is used to show the results with the Thermally thick approximation option. Later, another study will use Thin Layer 2 with the General option.
4
In the tree, select Component 2 (comp2) > Heat Transfer in Solids 2 (ht2) > Thin Layer 2.
5
Click  Disable.
Mesh 2
In the Model Builder window, under Component 2 (comp2) click Mesh 2.
Free Triangular 1
1
In the Mesh toolbar, click  More Generators and choose Free Triangular.
2
Select Boundaries 7 and 10 only.
3
In the Settings window for Free Triangular, click  Build Selected.
Swept 1
1
In the Mesh toolbar, click  Swept.
2
In the Model Builder window, right-click Mesh 2 and choose Build All.
Study 2
In the Study toolbar, click  Compute.
Results
Temperature Profile
In the Model Builder window, expand the Results > Temperature (ht2) node, then click Results > Temperature Profile.
Line Graph 2
1
Right-click Temperature Profile and choose Line Graph.
2
In the Settings window for Line Graph, locate the Data section.
3
From the Dataset list, choose Study 2/Solution 2 (3) (sol2).
4
Select Edges 9 and 11 only.
5
Click Replace Expression in the upper-right corner of the y-Axis Data section. From the menu, choose Component 2 (comp2) > Heat Transfer in Solids 2 > Temperature > T2 - Temperature - K.
6
Locate the x-Axis Data section. From the Parameter list, choose Expression.
7
In the Expression text field, type z.
8
Locate the Coloring and Style section. Find the Line style subsection. From the Line list, choose None.
9
From the Color list, choose Magenta.
10
Find the Line markers subsection. From the Marker list, choose Cycle.
11
From the Positioning list, choose Interpolated.
12
In the Number text field, type 15.
13
Locate the Legends section. Select the Show legends checkbox.
14
From the Legends list, choose Manual.
15
In the table, enter the following settings:
Legends
Temperature, 2D Approach
16
In the Temperature Profile toolbar, click  Plot.
Temperature, 2D Approach
1
In the Model Builder window, under Results click Temperature (ht2).
2
In the Settings window for 3D Plot Group, type Temperature, 2D Approach in the Label text field.
Next, add a study to solve Component 2 with Thin Layer 2 instead of Thin Layer 1. The Thin Layer 2 feature would use the General option which creates a 1D extra dimension formed by two intervals to represent the two ceramic layers.
Add Study
1
In the Home toolbar, click  Add Study to open the Add Study window.
2
Go to the Add Study window.
3
Find the Studies subsection. In the Select Study tree, select General Studies > Stationary.
4
Find the Physics interfaces in study subsection. In the table, clear the Solve checkbox for Heat Transfer in Solids (ht).
5
Click the Add Study button in the window toolbar.
6
In the Home toolbar, click  Add Study to close the Add Study window.
Study 3
Step 1: Stationary
1
In the Settings window for Stationary, locate the Physics and Variables Selection section.
2
Select the Modify model configuration for study step checkbox.
3
In the tree, select Component 2 (comp2) > Heat Transfer in Solids 2 (ht2) > Thin Layer 1.
4
Click  Disable.
5
In the Study toolbar, click  Compute.
Results
Temperature Profile
In the Model Builder window, expand the Results > Temperature (ht2) node, then click Results > Temperature Profile.
Line Graph 3
1
In the Temperature Profile toolbar, click  Line Graph.
2
In the Settings window for Line Graph, locate the Data section.
3
From the Dataset list, choose Study 3/Solution 3 (5) (sol3).
4
Select Edges 9 and 11 only.
5
Locate the y-Axis Data section. In the Expression text field, type T2.
6
Locate the x-Axis Data section. From the Parameter list, choose Expression.
7
In the Expression text field, type z.
8
Locate the Coloring and Style section. Find the Line style subsection. From the Line list, choose None.
9
From the Color list, choose From theme.
10
From the Width list, choose 2.
11
Find the Line markers subsection. From the Marker list, choose Triangle.
12
From the Positioning list, choose Interpolated.
13
In the Number text field, type 20.
14
Locate the Legends section. Select the Show legends checkbox.
15
From the Legends list, choose Manual.
16
In the table, enter the following settings:
Legends
Temperature, 2D with extra dimension approach
17
In the Temperature Profile toolbar, click  Plot.
The plot should look like Figure 3.
Create a group for current and forthcoming plots corresponding to the 2D with extra dimension approach.
Temperature (ht2)
In the Model Builder window, under Results right-click Temperature (ht2) and choose Group.
2D With Extra Dimension Approach
In the Settings window for Group, type 2D With Extra Dimension Approach in the Label text field.
Also, place the plot comparing the different approaches under a specific node.
Temperature Profile
In the Model Builder window, under Results right-click Temperature Profile and choose Group.
Comparison of the Different Approaches
In the Settings window for Group, type Comparison of the Different Approaches in the Label text field.
Next, create plots to compare more in details the results obtained with Study 1 and Study 3 for the temperature in the ceramic layers. In addition, evaluate the average of the thermal barrier temperature obtained with these two studies.
First, create a plot for the temperature solution at the surface of the thermal barrier.
Temperature (Layers Surface)
1
In the Results toolbar, click  3D Plot Group.
2
In the Settings window for 3D Plot Group, type Temperature (Layers Surface) in the Label text field.
3
Locate the Data section. From the Dataset list, choose Layered Material 2.
Surface 1
1
Right-click Temperature (Layers Surface) and choose Surface.
2
In the Settings window for Surface, locate the Coloring and Style section.
3
From the Color table list, choose HeatCameraLight.
4
In the Temperature (Layers Surface) toolbar, click  Plot.
For a better rendering, change the scaling factor for the thickness of the layers in the Layered Material 2 dataset.
Layered Material 2
1
In the Model Builder window, expand the Results > Datasets node, then click Layered Material 2.
2
In the Settings window for Layered Material, locate the Layers section.
3
In the Scale text field, type 20.
4
Click  Plot.
Temperature (Layers Surface)
1
In the Model Builder window, under Results > 2D With Extra Dimension Approach click Temperature (Layers Surface).
2
In the Settings window for 3D Plot Group, locate the Plot Settings section.
3
From the View list, choose New view.
2D With Extra Dimension Approach
Next, create a plot for the temperature on slices of the thermal barrier.
Temperature (Slices)
1
In the Results toolbar, click  3D Plot Group.
2
In the Settings window for 3D Plot Group, type Temperature (Slices) in the Label text field.
3
Locate the Data section. From the Dataset list, choose Study 3/Solution 3 (5) (sol3).
4
Locate the Plot Settings section. Clear the Plot dataset edges checkbox.
5
From the View list, choose New view.
Layered Material Slice 1
1
Right-click Temperature (Slices) and choose Layered Material Slice.
2
In the Settings window for Layered Material Slice, locate the Through-Thickness Location section.
3
From the Location definition list, choose Interfaces.
4
Locate the Layout section. From the Displacement list, choose Linear.
5
From the Orientation list, choose x.
6
In the Relative x-separation text field, type 0.25.
7
Select the Show descriptions checkbox.
8
In the Relative separation text field, type 1.
9
Locate the Coloring and Style section. From the Color table list, choose HeatCameraLight.
10
In the Temperature (Slices) toolbar, click  Plot.
11
Click the  Zoom Extents button in the Graphics toolbar.
Next, plot the temperature through the thickness of the thermal barrier.
Temperature (Through Thickness)
1
In the Results toolbar, click  1D Plot Group.
2
In the Settings window for 1D Plot Group, type Temperature (Through Thickness) in the Label text field.
Line Graph 1
1
Right-click Temperature (Through Thickness) and choose Line Graph.
2
Select Edges 4 and 7 only.
3
In the Settings window for Line Graph, locate the y-Axis Data section.
4
In the Expression text field, type z-(2[cm]-(d_ceram1+d_ceram2)/2).
5
From the Unit list, choose m.
6
Locate the x-Axis Data section. From the Parameter list, choose Expression.
Temperature (Through Thickness)
In the Model Builder window, click Temperature (Through Thickness).
Through Thickness 1
1
In the Temperature (Through Thickness) toolbar, click  More Plots and choose Through Thickness.
2
In the Settings window for Through Thickness, locate the Data section.
3
From the Dataset list, choose Study 3/Solution 3 (5) (sol3).
4
Select Point 2 only.
5
Locate the x-Axis Data section. In the Expression text field, type T2.
6
Click to expand the Coloring and Style section. Find the Line style subsection. From the Line list, choose None.
7
Find the Line markers subsection. From the Marker list, choose Cycle.
8
From the Positioning list, choose Interpolated.
9
Locate the y-Axis Data section. Find the Interface positions subsection. From the Show interface positions list, choose All interfaces.
10
In the Temperature (Through Thickness) toolbar, click  Plot.
Finally, evaluate the average temperature in the thermal barrier and in each of its layers by making a Global Evaluation of the variables defined previously in each component.
Global Evaluation 1
1
In the Results toolbar, click  Global Evaluation.
2
In the Settings window for Global Evaluation, click Replace Expression in the upper-right corner of the Expressions section. From the menu, choose Component 1 (comp1) > Definitions > Variables > T_ave_barrier - Average of temperature in thermal barrier - K.
3
Click Add Expression in the upper-right corner of the Expressions section. From the menu, choose Component 1 (comp1) > Definitions > Variables > T_ave_layer1 - Average of temperature in layer 1 - K.
4
Click Add Expression in the upper-right corner of the Expressions section. From the menu, choose Component 1 (comp1) > Definitions > Variables > T_ave_layer2 - Average of temperature in layer 2 - K.
5
Locate the Expressions section. In the table, enter the following settings:
Expression
Unit
Description
T_ave_barrier
degC
Average of temperature in thermal barrier
T_ave_layer1
degC
Average of temperature in layer 1
T_ave_layer2
degC
Average of temperature in layer 2
6
Click  Evaluate.
Global Evaluation 2
1
In the Results toolbar, click  Global Evaluation.
2
In the Settings window for Global Evaluation, locate the Data section.
3
From the Dataset list, choose Study 3/Solution 3 (5) (sol3).
4
Click Replace Expression in the upper-right corner of the Expressions section. From the menu, choose Component 2 (comp2) > Definitions > Variables > T_ave_barrier - Average of temperature in thermal barrier - K.
5
Click Add Expression in the upper-right corner of the Expressions section. From the menu, choose Component 2 (comp2) > Definitions > Variables > T_ave_layer1 - Average of temperature in layer 1 - K.
6
Click Add Expression in the upper-right corner of the Expressions section. From the menu, choose Component 2 (comp2) > Definitions > Variables > T_ave_layer2 - Average of temperature in layer 2 - K.
7
Locate the Expressions section. In the table, enter the following settings:
Expression
Unit
Description
T_ave_barrier
degC
Average of temperature in thermal barrier
T_ave_layer1
degC
Average of temperature in layer 1
T_ave_layer2
degC
Average of temperature in layer 2
8
Click  Evaluate.
The average temperature is close to 530°C in the thermal barrier, with some noticeable difference between the two layers.