Oil grooves are provided between the pads to supply the lubricant. Therefore, sets of a pad and a groove are repeated in the circumferential direction making the bearing sector symmetric with the sector angle 2π/
N, where
N is the number of the pads in the bearing. Let us consider a local
y direction passing through the leading edge of one of the pads and let
rc be the coordinate of the center of the bearing. Then for a point at position
r on the bearing pad, its radial and azimuthal coordinates are:
where e2 and
e3 are the local directions in the bearing. The first pad on the bearing is then located between
The ith pad will therefore be located between
The location of the pivot point for the ith pad from the bearing center is, in polar coordinates, given by
Denote the tilt angles of the ith pad about the radial and circumferential directions by
δir and
δic, respectively. Assuming that these tilt angles are small, the tilt vector can be written as
are the radial and circumferential directions on the ith pad. Due to tilting of the pad, the displacement at a point
X on the pad surface is
Here Xip is the position vector of the pivot point of the
ith pad with respect to bearing center,
If the film thickness at the pivot point is hp then the film thickness due to tilting at a point
X on the pad due to tilting will be
For the pad with sector angle γ, inner radius
ri, outer radius
ro, and thickness
tp, and the pivot locations specified as above, the mass moment of inertia components about the pivot point are given by